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Wanna work at google?

#21 User is offline   Codo 

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Posted 2007-September-21, 07:43

Fluffy, on Sep 21 2007, 05:23 PM, said:

[i]1. How many golf balls can fit in a school bus?

17.234

2. You are shrunk to the height of a nickel and your mass is proportionally reduced so as to maintain your original density. You are then thrown into an empty glass blender. The blades will start moving in 60 seconds. What do you do?

pray -unlucky I don´t know what a glass blender is, nor do I know a nickle but praying often helps.

3. How much should you charge to wash all the windows in Seattle?

around 4 Mill windows? 40.000.000 Dollar?

4. How would you find out if a machine’s stack grows up or down in memory?

They always grow down. Better english may had helped to understand the question.

5. Explain a database in three sentences to your eight-year-old nephew.

Your uncle has shown you his old chess journals. A database is a big journal inside a computer. There are journals for any point of interest- and for all others.

6. How many times a day does a clock’s hands overlap?

23 times

7. You have to get from point A to point B. You don’t know if you can get there. What would you do?

Take the first step and take it from there.

8. Imagine you have a closet full of shirts. It’s very hard to find a shirt. So what can you do to organize your shirts for easy retrieval?

I install a website with a photo of each shirt on the internet. And then I google them. Google will find anything.

9. Every man in a village of 100 married couples has cheated on his wife. Every wife in the village instantly knows when a man other than her husband has cheated, but does not know when her own husband has. The village has a law that does not allow for adultery. Any wife who can prove that her husband is unfaithful must kill him that very day. The women of the village would never disobey this law. One day, the queen of the village visits and announces that at least one husband has been unfaithful. What happens?

Every women knewd before that there are 99 cheaters. So they just say: What´s new?

10. In a country in which people only want boys, every family continues to have children until they have a boy. if they have a girl, they have another child. if they have a boy, they stop. what is the proportion of boys to girls in the country?

2:1 was my guess, but this is false. About 1:1

11. If the probability of observing a car in 30 minutes on a highway is 0.95, what is the probability of observing a car in 10 minutes (assuming constant default probability)?

depends on the model. No not the model of the car, the model you use for your simulation. I go with about 66 %.

12. If you look at a clock and the time is 3:15, what is the angle between the hour and the minute hands? (The answer to this is not zero!)
7.5 degree

13. Four people need to cross a rickety rope bridge to get back to their camp at night. Unfortunately, they only have one flashlight and it only has enough light left for seventeen minutes. The bridge is too dangerous to cross without a flashlight, and it’s only strong enough to support two people at any given time. Each of the campers walks at a different speed. One can cross the bridge in 1 minute, another in 2 minutes, the third in 5 minutes, and the slow poke takes 10 minutes to cross. How do the campers make it across in 17 minutes?

B+a+C+a+D=19...I Knew there was a solution, but I do not get it.

14. You are at a party with a friend and 10 people are present including you and the friend. your friend makes you a wager that for every person you find that has the same birthday as you, you get $1; for every person he finds that does not have the same birthday as you, he gets $2. would you accept the wager?

Well, I lead 1:0, but I need 5 persons out 9 with the same birthday for a tie..

15. How many piano tuners are there in the entire world?

15.000 ?

16. You have eight balls all of the same size. 7 of them weigh the same, and one of them weighs slightly more. How can you find the ball that is heavier by using a balance and only two weighings? 3/3 1/1 as stated before

17. You have five pirates, ranked from 5 to 1 in descending order. The top pirate has the right to propose how 100 gold coins should be divided among them. But the others get to vote on his plan, and if fewer than half agree with him, he gets killed. How should he allocate the gold in order to maximize his share but live to enjoy it? (Hint: One pirate ends up with 98 percent of the gold.)

I guess the solution is something like: 98:0:1:1:0 and the reasoning is this:
He tells the next pirates, what will happen if he is killed. Nr. 2 Will become the leader:
LEts start from behind:
If 5 and 4 survive, 4 will get all the money.
If 543 survive, 3 can take 99 and give Nr. 5 1.
If 5432 survive, 2 can take 97 and give 4 1 and 5 2
SO to survive Nr. 1 must take 97 pcs. and give 4 2 and 3 one pcs. Then these both will get more then 2 may offer them. If they are fine with the Nr. 1 pirate, he may as well offer them both just 1 Dollar. But this would be too risky for me.
Kind Regards

Roland


Sanity Check: Failure (Fluffy)
More system is not the answer...
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#22 User is offline   hrothgar 

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Posted 2007-September-21, 08:05

About these types of interviews:

Questions like "How many ping pong balls fit into a school bus" aren't intended to test obscure facts. Rather they determine how good you are at different types of problem solving.

Is there a quick/effective way to determine how many ping pong balls fit into a schoolbus beyond exhaustive search? Random guesses without accompanying explanations aren't viewed kindly.

Being able to explain that

A + B cross the bridge
A returns

C + D cross the bridge
B returns

A + B cross the bridge

are viewed favorably

Being able to relate this type of problem back to Tower of Hanoi is more favorable...
Alderaan delenda est
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#23 User is offline   bid_em_up 

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Posted 2007-September-21, 09:45

7. You have to get from point A to point B. You don’t know if you can get there. What would you do?

Look it up on Google Maps. :D
Is the word "pass" not in your vocabulary?
So many experts, not enough X cards.
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#24 User is offline   jtfanclub 

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Posted 2007-September-21, 09:47

Codo, on Sep 21 2007, 08:43 AM, said:

2. You are shrunk to the height of a nickel and your mass is proportionally reduced so as to maintain your original density. You are then thrown into an empty glass blender. The blades will start moving in 60 seconds. What do you do?

5. Explain a database in three sentences to your eight-year-old nephew.

13. Four people need to cross a rickety rope bridge to get back to their camp at night. Unfortunately, they only have one flashlight and it only has enough light left for seventeen minutes. The bridge is too dangerous to cross without a flashlight, and it’s only strong enough to support two people at any given time. Each of the campers walks at a different speed. One can cross the bridge in 1 minute, another in 2 minutes, the third in 5 minutes, and the slow poke takes 10 minutes to cross. How do the campers make it across in 17 minutes?

2. Sit on top of the middle of the blender (where the blades join). The wind from the blades will throw you out of the blender.

5. It's a cabinet where information you need is stored so that it's easy to find. Usually, it's arranged by size, or alphabetical order, or color, or something. Do you like ice cream?

13. Pokey dude and fast dude go across.
Fast dude goes back with the flashlight...AT THE SAME TIME, the 2nd fast guy goes across in the other direction. Then, when the 2nd fastest guy finishes, the 1st guy and the 2nd slowest guy go across.

Yeah, it's a trick, so what?
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#25 User is offline   rona_ 

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Posted 2007-September-21, 09:50

Fluffy, on Sep 21 2007, 12:44 PM, said:

can someone help me with number 2?, I can't transate it properly.

nickell is a coin?

glass blender I have no idea of what it is

Fluffy,

A nickel is a US 5 cents coin.

A blender is a kitchen gadget that liquifies food, so I am guessing that a glass blender is a blender with a glass jar to put the food in. Come to think of it, I have only seen glass ones. :rolleyes:
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#26 User is offline   Fluffy 

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Posted 2007-September-21, 13:10

david_c, on Sep 21 2007, 01:03 PM, said:

Fluffy, on Sep 21 2007, 09:23 AM, said:

17. You have five pirates, ranked from 5 to 1 in descending order. The top pirate has the right to propose how 100 gold coins should be divided among them. But the others get to vote on his plan, and if fewer than half agree with him, he gets killed. How should he allocate the gold in order to maximize his share but live to enjoy it? (Hint: One pirate ends up with 98 percent of the gold.)kes to work for Google?

Dammit I get 97. Can someone explain what I've done wrong here:

with three remaining: -, -, 100, 0, 0
with four remaining: -, 98, 0, 1, 1
with five remaining: 97, 0, 1, 2, 0 or 97, 0, 1, 0, 2.

I came to this as well

But then think of the 2 pirate problem

what would 1 do if '2' offered him 100 coins and 0 for him? He doesn't care to pick to pick the 100 now, or just kill the other and pick the 100 after, your solution says he would always die, but that doesn't have to these way.

Bad new is that even then, the result comes to 97-2-1 at the end :rolleyes:, but I think changing the way to solve ties leads to 98.

Also they said 98% of the gold, there is a famous similar problem wich ends with '33-33-33, and throw the 100th to the sea so nobody gets angry'

98% could stand for 97/99 I guess, it can be a point to take :)


What amsued me the most of this problem is that I first though 98 coins would probably go to the second or first.

Upon starting to solve I suspected for to the third or fouth, I was in bed a bit sleep, but untill the very end when I solved step 5 I didn't realice it was the original pirate to get almost all of the gold :). It hit me in the face, was fun.
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#27 User is offline   Fluffy 

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Posted 2007-September-21, 13:17

number 2:

there is no liquid, only air, the ebst you can do is move into the middle of the glass to get into the 'eye' of the 'tornado'?
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#28 User is offline   jtfanclub 

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Posted 2007-September-21, 14:18

Fluffy, on Sep 21 2007, 02:17 PM, said:

number 2:

there is no liquid, only air, the ebst you can do is move into the middle of the glass to get into the 'eye' of the 'tornado'?

Don't have to.

The blades in a blender spin like a helocopter, pushing everything up. This means the heaviest stuff stays at the bottom and gets chopped up. If you run a blender with the lid off, you get a nice coat of whatever on the ceiling.
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#29 User is offline   pdmunro 

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Posted 2007-September-22, 00:29

helene_t, on Sep 21 2007, 07:52 AM, said:

Funny, I recall Google was chosen as the most attractive US employer by some fancy magazine a couple of years ago. Maybe that position has made them arrogant.

I have read that Google interviews are technical. For example:

"Ok, regarding the interviews, yes they are tough. They grill you with specifics, so you really have to know your stuff.

Skills like C++ and Java were only secondary requirements for me, the main requirement being a different platform (I hesitate to mention it here, it would be too damning to me) so I can not give much specifics that would help most of you out there (plus I have to worry about the Non Disclosure agreement that I signed).

The phone interview was around 40 minutes. It was technical, but wasn't too in-depth. I think the guy sensed I knew my stuff, so he didn't really grill me.

On site interviews lasted almost 4 hours, and were rather grilling. Much of the technical questions they asked me were real design issues they were facing. They use whiteboards often, which was really cool for me, because I like hammering out solutions as I write and draw. They didn't throw any of the (in)famous puzzles that I hear about, nor did they try any kind of personality tests. They just grilled me on the platform that is my main expertise."
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#30 User is offline   rbforster 

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Posted 2007-September-22, 01:43

david_c, on Sep 21 2007, 08:03 AM, said:

Dammit I get 97. Can someone explain what I've done wrong here:

with three remaining: -, -, 100, 0, 0
with four remaining: -, 98, 0, 1, 1
with five remaining: 97, 0, 1, 2, 0 or 97, 0, 1, 0, 2.

This pirates problem depends on 2 important things - how ties get broken, and what the incentives of the pirates are when faced with an equal $ choice. In the =>50% to win case, there are never issues with ties (they are broken in favor of the proposing pirate), and you get the recursive solution like this

-- -- -- 100 0 (sucks to be last)
-- -- 99 0 1
-- 99 0 1 0
98 0 1 0 1

In this case 98 is the right answer, and there are no issues with the pirates incentives in case of a tie. If you use the strictly >50% to win rule, and you assume that incentives are ordered Live > $ > Kill Others, then you get 97.

-- -- -- X 100 (X = killed)
-- -- 100 0 0 (#4 votes in favor, to avoid dying)
-- 98 0 1 1
97 0 1 2 0 (or 97 0 1 0 2)
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#31 User is offline   Echognome 

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Posted 2007-September-22, 03:05

Fluffy, on Sep 21 2007, 12:23 AM, said:

17. You have five pirates, ranked from 5 to 1 in descending order. The top pirate has the right to propose how 100 gold coins should be divided among them. But the others get to vote on his plan, and if fewer than half agree with him, he gets killed. How should he allocate the gold in order to maximize his share but live to enjoy it? (Hint: One pirate ends up with 98 percent of the gold.)

I am going to stick my neck out and say you are all wrong (except possibly David C and Rob F) on this.

First comment, this is NOT the same as the classic five pirate problem where the proposer gets to vote. Note that in the setup of this problem, the proposer doesn't vote, but the others do. And if fewer than half of those that vote agree with him, he is killed. (It is not stated, but assumed that if half or more do agree, then the proposal is accepted.)

Second comment, no discussion of ties is discussed. Furthermore, beliefs are not discussed. Let me propose a Nash equilibrium. Pirate A proposes 100, 0, 0, 0, 0. Pirates B, C, D, and E all vote yes and they all believe all of the other pirates are going to vote yes. Given their beliefs (which are true in equilibrium), they have no incentive to vote no (because it will not change the outcome). No need for any backward induction at all! There are, of course, other equilibria.

Third comment, so let's do this the way the problem was intended and say you must break ties with at least one gold coin. Then let's apply backward induction as it was meant to be.

If only D and E left, E will not accept any offer less than 100. Why would he when he could just vote no and D is killed. (If he votes no, then fewer than half of the others agree with the proposer, D.) So the only equilibrium is:
(dead, dead, dead, 0, 100)

If C, D, and E are left, then D will accept any proposal where he gets more than 0 (lest he get nothing at all, or even worse, killed). So for C to maximize his gold, he only need to offer D one golf coin. Since C needs only 1 out of 2 votes, he can do no better than the equilibrium:
(dead, dead, 99, 1, 0)

If B, C, D, and E are left, then B knows that he needs to get 2 out of the 3 votes to have his proposal accepted. So the best he can do is offer the equilibrium:
(dead, 97, 0, 2, 1)

If all five pirates are left, then A needs only 2 out of 4 votes to have his proposal accepted. The cheapest votes he can buy are C's and E's, so the best he can do is propose:
(97, 0, 1, 0, 2)
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#32 User is offline   Joe de Balliol 

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Posted 2007-September-22, 04:26

I agree with Echognome...BUT, I don't see any incentive to give E 2 rather than 1 - E will get 1 from either B or A so has no incentive to not accept A's proposal, and the slight negative incentive that if neither A nor B's proposal is accepted, he will get nothing, so is likely to accept 1 - maybe this is why the problem says 98? Or, as Echognome pointed out, it might be from the alternative form where all pirates vote.
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#33 User is offline   Blofeld 

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  Posted 2007-September-22, 04:36

As pointed out, some of these problems seem to have been garbled from their standard forms, presenting us with either a problem with not enough information or one with a trivial solution.

I'll skip the large-numbers-estimations because I'd encourage others to try these (they're fun and not too hard). But some of the other questions haven't been adequately answered, I think, so I'll have a go.

2. Standing on the blades seems to be asking for trouble. For one thing, my experience of blenders tells me that stuff is sucked down in the middle (and thrown up around the edges). At any rate the net airflow up/down must be zero. I'd rather not get stuck in a turbulent flow of this kind when another option presents itself:

I jump out. I'm not quite sure how big a nickel is, but it doesn't matter. Say we're being shrunk to 1/n of our normal size in linear dimensions. Then muscle strength, which is proportional to cross-sectional area, will be 1/n^2 normal. Our legs will be able to push us from the ground for 1/n the normal distance. Using E = Fs (E = Energy, F = force, s = displacement) to get kinetic energy gained from jumping, we should have 1/n^3 the normal amount. But our mass is also 1/n^3 normal, so when we leave the ground our velocity is just the same as when we jump at full size. If we neglect air resistance we'd thus be able to jump to the same height. Air resistance will play a bigger role on small-us, but not sufficiently big that we shouldn't be able to clear the blender walls.

9. If we assume that everyone involved is entirely logical and knows all the others to be so, then on the hundredth day all the wives kill their husbands. [Claim: if precisely n husbands have been unfaithful then their wives will kill them on the nth day. Obviously true for n=1. Proceed by induction.]

11. Probability of not observing a car in 30 minutes = 0.05. Therefore probability of not observing a car in 10 minutes has to be the cube root of 0.05. Probability of observing a car in 10 minutes is 1 minus this, or roughly 0.63.
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#34 User is offline   Fluffy 

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Posted 2007-September-22, 06:32

you come to 98 coins if you asume people won't put their life in danger for no gain.

Pirate 2 would then accepet Anything so

100-0-0 is good

99-0-0-1 is good

99-0-1-0-0 is also good

Right?

No, pirate 2 has another chance of accepting 0 later, then he wouldn't accept getting 0 untill the last time at 100-0-0 since he has the chance of someone doing it wrong.
so.

100-0-0 is good

98-0-1-1 is good

----

97-0-1-2-0 or 97-0-1-0-2 :/


bah!


Another idea: If there are 2 solutions for an early case, you can offer the same ammount he gets on a previous round, because he doesn't know if he will get the same, or less.
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#35 User is offline   hotShot 

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Posted 2007-September-22, 08:58

Quote

17. You have five pirates, ranked from 5 to 1 in descending order. The top pirate has the right to propose how 100 gold coins should be divided among them. But the others get to vote on his plan, and if fewer than half agree with him, he gets killed. How should he allocate the gold in order to maximize his share but live to enjoy it? (Hint: One pirate ends up with 98 percent of the gold.)

So pirate5 has to make he first suggestion and pirate1 will be the last.

This means:
Pirate1's live is in no danger and if he does not accept offers of less than 100, he will get all in the end.
Pirate2's live is in no danger, but he will have to offer pirate1 100, to stay alive. So he will accept any offer better than nothing.
Pirate3 is sort of a lucky guy, he knows pirate1 will reject his offer, but if pirate2 agrees, his live is save and he lives to spent his money. So in his position 99-1-0 would work.
So he does not need to agree to anything less than 99 coins.
Pirate4 is in a bad position, he knows that pirate3 and pirate1 will disagree with almost any suggestion he can make (maybe 0-99-1-0 would work). So his live is at risk if he does not agree to anything that pirate5 suggests.
So pirate5 will stay alive if he offers pirate4 and pirate2 a coin and keeping their lives.
So the solution is 98-1-0-1-0.
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#36 User is offline   matmat 

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Posted 2007-September-22, 11:38

Blofeld, on Sep 22 2007, 05:36 AM, said:

I jump out. I'm not quite sure how big a nickel is, but it doesn't matter. Say we're being shrunk to 1/n of our normal size in linear dimensions. Then muscle strength, which is proportional to cross-sectional area, will be 1/n^2 normal. Our legs will be able to push us from the ground for 1/n the normal distance. Using E = Fs (E = Energy, F = force, s = displacement) to get kinetic energy gained from jumping, we should have 1/n^3 the normal amount. But our mass is also 1/n^3 normal, so when we leave the ground our velocity is just the same as when we jump at full size. If we neglect air resistance we'd thus be able to jump to the same height. Air resistance will play a bigger role on small-us, but not sufficiently big that we shouldn't be able to clear the blender walls.

sorry. the lid was closed.
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#37 User is offline   paulg 

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Posted 2007-September-22, 13:44

It's my guess that your answer has to be on the first page of responses to be considered for a job with Google.

Paul
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I don't work for BBO and any advice is based on my BBO experience over the decades
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#38 User is offline   cherdano 

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Posted 2007-September-22, 13:57

cardsharp, on Sep 22 2007, 01:44 PM, said:

It's my guess that your answer has to be on the first page of responses to be considered for a job with Google.

Paul

You didn't know they always invite the author of the 37th response to an interview?
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#39 User is offline   han 

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Posted 2007-September-22, 14:20

Blofeld, on Sep 22 2007, 05:36 AM, said:

11. Probability of not observing a car in 30 minutes = 0.05. Therefore probability of not observing a car in 10 minutes has to be the cube root of 0.05. Probability of observing a car in 10 minutes is 1 minus this, or roughly 0.63.

Well done Owen.
Please note: I am interested in boring, bog standard, 2/1.

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#40 User is offline   sceptic 

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Posted 2007-September-22, 20:08

The pirates

Question

= 1 one of us gets 98 coins, 1 gets 1 coin another gets 1 coin , the rest get zero

Lets have a lottery


answer "ok yes lets go for it"
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