In last night's Robot duplicate, no pair managed to reach slam (not even the 6-level). Any idea how these can be bid to a grand slam?
14 tricks
#1
Posted 2010-September-06, 03:34
In last night's Robot duplicate, no pair managed to reach slam (not even the 6-level). Any idea how these can be bid to a grand slam?
#2
Posted 2010-September-06, 04:07
-- Bertrand Russell
#3
Posted 2010-September-06, 05:42
Roland
Sanity Check: Failure (Fluffy)
More system is not the answer...
#4
Posted 2010-September-06, 09:29
♠ A2
♥ 95
♦ QJ4
♣ QT8762
♠ T7
♥ AT
♦ AK8653
♣ AKJ
p - 1D
1NT - 3C! ( GF, maybe artificial )
3H! ( relay ) - 3S! ( completing relay )
4C! ( double fit: 3+d / 4+c ) - 4D! ( 6 Ace RKC )
4S! ( 2nd step = 1 key ) - 4NT! ( Q's ask )
??
5C! = neither Cl or Diam Q
5D! = 1 Q
5H! = 2 Q's
5H! - 5S! ( specific K-ask; either Major K enough for the grand )
6C! ( no K's ) - 6NT ( can only count to a sure 12: 1s, 1h, 6d, 4c )
#5
Posted 2010-September-06, 09:48
#6
Posted 2010-September-06, 09:51
p - 1D
2C ( 5+c, values, no 4M ) - 2H
2S - 4C! ( Minorwood )
4H! (2nd step = 1 key ) - 4S! ( next step = cQ-ask )
5D! ( cQ and either dK or dQ; denies hK or sK ) - 6C ( not sure how many Diam will come in--may need to ruff a Diam to set up )
#7
Posted 2010-September-07, 04:11
ONEferBRID, on Sep 6 2010, 04:51 PM, said:
p - 1D
2C ( 5+c, values, no 4M ) - 2H
2S - 4C! ( Minorwood )
4H! (2nd step = 1 key ) - 4S! ( next step = cQ-ask )
5D! ( cQ and either dK or dQ; denies hK or sK ) - 6C ( not sure how many Diam will come in--may need to ruff a Diam to set up )
I wonder which meaning of the word "conventional" you meant to convey here.
-- Bertrand Russell
#8
Posted 2010-September-07, 04:30
#9
Posted 2010-September-07, 05:15
3♣ - 4♣ -
4♦ - 4NT -
5♥ - 7NT
3♣ ostensibly natural, but includes hands like above.
4♣ good clubs and slam interest
4♦ showing great hand with primary diamonds. (2 clubs only when 7222, otherwise 3)
4NT 6 key RKC
5H 2 or 5 without either Queen.
7NT lol, you can't have 2 aces for this bidding
Natural did better this time than my relay methods:
2♣ - 2♦ -
3♣ - 3♦ -
3♥ - 3♠ -
4♣ - 4♦ -
4♥ - 4♠ -
4NT
2♣ natural clubs, may have ♦s
3♣ shows the shape
3♥ 5 AKQ points
4♣ even number of kings and no ♣ control
4♥ No ♦ control
4NT No ♥ control
So now ♠A is known and that there are two queens. Problem is that 5♣ relay would take us to 5♥ minimum. I think it's strongly odds on that there is at least one minor queen but do you want to play 6 then? But if there are 2, you wanna play 7NT. Now that I think of it bit more (probably wouldn't come this far in table) it's possible to stop in 5NT after no minor Qs. So I guess it's good to relay once more... and you get it all.
5♣ - 5NT = ♠A and minor queens - 7NT
#10
Posted 2010-September-07, 05:38
AQ
QJ
Jxx
xxxxxx
really be an opener for you?
George Carlin
#11
Posted 2010-September-07, 05:56
Mainly I though about AQ xx Qxx xxxxxx being a possible problem.

Help

The board whizzed by in 30 seconds.
North South
Pass - 1♦
1NT - 3NT
all pass
Robot North plays out the board in 20 seconds for +520.