gwnn, on 2016-April-28, 07:01, said:
Publication date 26 Aug 1985
Seems like yesterday, but it was long ago.....
I'm older now but still running against the wind--- Bob Seeger
Anyway, back to the OP..
Many hands can be handled reasonably without conventions. This isn't one of them. If 2D is not agreed to be artificial and forcing, or if you are not sure whether partner treats it that way, I don't know what you should do. Even if 2D is forcing there could be problems. You bid 2D he bids 2H. For some this denies three spades. For others, holding four hearts and three spades they start by bidding 2H. Of course (?) after 2D-2H a bid of 3C should be natural and forcing, and it gives him room to show his three spades if he has them. If, instead, he bids 2S over 2D I suppose that shows not only that he has three spades but that he has a minimum. If he had a max he could have bid 3S.
But if partner has the club Q and Qxx in spades I can already count a probable nine tricks and I have accounted for only four of partner's presumes 12 count. If he has the two red aces I am up to 12 tricks.
But that's placing a lot of specific cards in his hand.
Anyway, I start with 2D if it is known to be forcing. If nothing is known to be forcing then I dunno, I probably just bid 4S. If I don't have tools, I make my best guess. Or what appears to me to be my best guess. It would not amaze me if 6C is on ice, but how to see when it is and when it isn't?
An observation: If partner does not have either three spades or four hearts then he has four clubs. Actually he has five clubs if he opens 1D when he is 4-4 in the minors. So if it starts 1C-1S-1N-2D-2NT I will be very optimistic about a club slam. My next call would be 3C as long as I need not worry partner will pass it. Kx in hearts will stop them from taking the first two tricks in hearts in 6C, which is not the case in 6S.
Anytime he doesn't have three spades he has four clubs.